Question #c4bd2

1 Answer
Jim G.
Apr 7, 2017

#f'(x)=-sin(lnx)/x#

Explanation:

differentiate using the #color(blue)"chain rule"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(f(g(x)))=f'(g(x))xxg'(x))color(white)(2/2)|)))#

#rArrd/dx(cos(lnx))=-sin(lnx)xxd/dx(lnx)#

#color(white)(rArrd/dx(cos(lnx)))=-sin(lnx)xx1/x#

#color(white)(rArrd/dx(cos(lnx)))=-sin(lnx)/x#

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