# Question #a214a

Apr 7, 2017

$\text{Molarity} \cong 0.4 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

$\text{Molarity"="Moles of solute"/"Volume of solution}$.

$= \frac{\frac{50 \cdot g}{158.03 \cdot g \cdot m o {l}^{-} 1}}{800 \times {10}^{-} 3 \cdot L} \cong 0.4 \cdot m o l \cdot {L}^{-} 1$ with respect to $\text{potassium permanganate}$. What is the colour of this solution.