Question #63626

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Question #63626

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Answer 1 · 2017-04-09T09:20:05

$V = 72 \sqrt{3} f t^{3}$ $V=72sqrt3 ft^3$

Explanation:

Given that all sides are of equal length and all interior angles are of equal size, the hexagon is a regular hexagon.

Area of a regular hexagon $A = \frac{3 \sqrt{3}}{2} a^{2}$ $A=(3sqrt3)/2a^2$
where $a$ $a$ is the side length of the hexagon.

$\Rightarrow A = \frac{3 \sqrt{3}}{2} \cdot 4^{2} = 24 \sqrt{3} f t^{2}$ $=> A=(3sqrt3)/2*4^2=24sqrt3 ft^2$

Volume $V = A r e a \times h e i g h t$ $V = Area xx height$
given height $= 3$ $=3$
$\Rightarrow V = 24 \sqrt{3} \cdot 3 = 72 \sqrt{3} f t^{3}$ $=> V=24sqrt3*3=72sqrt3 ft^3$

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Question #63626

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