# Question ba724

Apr 10, 2017

graph{y=-8x-1 [-10, 10, -5, 5]}
slope of $- \frac{8}{1}$
y-int = (0,-1#)

#### Explanation:

$- 1$ is the intercept on the y axis, which the line passes through.
$- 8$ is the slope of the line.

In this case, since $m = - 8 = - \frac{8}{1}$,

from $\left(0 , - 1\right)$ you must move down $8$ units and then go right $1$ unit to give a negative slope.

The the rule of slope is $\text{rise"/" run}$ or $\text{change in y"/"change in x}$.