# Find the equation of normal and tangent to the circle #x^2+y^2=4# at the point #(2cos45^@,2sin45^@)#?

##### 1 Answer

Equation of normal is

#### Explanation:

We are seeking a tangent and normal from a point

Normal to a point on a circle is the line joining center to the given point. Asthe center of

Its slope is

So our tangent passes through

graph{(x+y-2sqrt2)(x-y)(x^2+y^2-4)=0 [-4.667, 5.333, -2.32, 2.68]}