# What mass of "potassium chloride" would result from the redox reaction of "potassium chlorate"? How is the reaction represented stoichiometrically?

Apr 11, 2017

We interrogate the reaction:

$K C l {O}_{3} \left(s\right) + \Delta \stackrel{M n {O}_{2}}{\rightarrow} K C l \left(s\right) + \frac{3}{2} {O}_{2} \left(g\right) \uparrow$

We would get approx. $16 \cdot g$ of salt.............

#### Explanation:

Often a little $\text{manganese(IV) oxide}$ is added to these reactions, as an oxygen transfer reagent, i.e. a catalyst.

Given the stoichiometry, moles of $\text{potassium chloride}$ produced are CLEARLY equal to the moles of $\text{potassium chlorate}$ reacted. Agreed?

$\text{Moles of potassium chlorate} = \frac{27 \cdot g}{122.6 \cdot g \cdot m o {l}^{-} 1} = 0.220 \cdot m o l$

And thus $\text{moles of potassium chloride}$

=0.220*molxx74.55*g*mol^-1=??*g