What mass of #"potassium chloride"# would result from the redox reaction of #"potassium chlorate"#? How is the reaction represented stoichiometrically?

1 Answer
Apr 11, 2017

Answer:

We interrogate the reaction:

#KClO_3(s) + Delta stackrel(MnO_2)rarrKCl(s) + 3/2O_2(g)uarr#

We would get approx. #16*g# of salt.............

Explanation:

Often a little #"manganese(IV) oxide"# is added to these reactions, as an oxygen transfer reagent, i.e. a catalyst.

Given the stoichiometry, moles of #"potassium chloride"# produced are CLEARLY equal to the moles of #"potassium chlorate"# reacted. Agreed?

#"Moles of potassium chlorate"=(27*g)/(122.6*g*mol^-1)=0.220*mol#

And thus #"moles of potassium chloride"#

#=0.220*molxx74.55*g*mol^-1=??*g#