Question #f9cf5

1 Answer
Apr 14, 2017

Answer:

#2.50*mol# of #CaCl_2# are necessary..........................

Explanation:

We use the relationship:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#.

And thus #"Moles of solute"="Concentration"xx"Volume of solution"#

#=5*mol*L^-1xx500*mLxx10^-3*L*mL^-1=2.50*mol#

What is the mass of this molar quantity?