# What mass is represented by 14.8*mol "barium chromate", and by 1.23xx10^22 chlorine molecules?

Apr 12, 2017

We have under $4 \cdot k g$ of $\text{barium chromate}$............and under $2 \cdot g$ of $C {l}_{2}$.

#### Explanation:

The molar mass of $\text{barium chromate}$ is $253.37 \cdot g \cdot m o {l}^{-} 1$. And thus the mass of the given quantity is $14.8 \cdot \cancel{m o l} \times 253.37 \cdot g \cdot \cancel{m o {l}^{-} 1} = 3750 \cdot g$.

For the $C {l}_{2}$ molecule, we solve the quotient:

$\left(1.23 \times {10}^{22} \cdot \text{chlorine molecules")/(6.022xx10^23*"chlorine molecules} \cdot m o {l}^{-} 1\right) = 0.0204 \cdot m o l$.

Since the chlorine molecule has a molar mass of $70.90 \cdot g \cdot m o {l}^{-} 1$, the mass of dichlorine is $70.90 \cdot g \cdot m o {l}^{-} 1 \times 0.0204 \cdot m o l = 1.45 \cdot g$