Question

What mass is represented by `14.8*mol` `"barium chromate"`, and by `1.23xx10^22` chlorine molecules?

Answer 1

We have under `4*kg` of `"barium chromate"`............and under `2*g` of `Cl_2`.

Explanation:

The molar mass of `"barium chromate"` is `253.37*g*mol^-1`. And thus the mass of the given quantity is `14.8*cancel(mol)xx253.37*g*cancel(mol^-1)=3750*g`.

For the `Cl_2` molecule, we solve the quotient:

`(1.23xx10^22*"chlorine molecules")/(6.022xx10^23*"chlorine molecules"*mol^-1)=0.0204*mol`.

Since the chlorine molecule has a molar mass of `70.90*g*mol^-1`, the mass of dichlorine is `70.90*g*mol^-1xx0.0204*mol=1.45*g`