How much carbon dioxide is released when a #1*L# volume of octane is combusted?

1 Answer
Apr 12, 2017

Answer:

Let us suppose that we use a #1*L# of octane to when we drive our motor...............

Explanation:

We reproduce your given equation:

#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#

I halved the stoichiometric equation to make the arithmetic a bit easier.

#"Moles of octane"# #=# #(1*cancelLxx10^3*cancel(mL*L^-1)xx0.703*cancel(g*mL^-1))/(114.24*cancelg*mol^-1)=6.15*mol#

And given the stoichiometry, #"FOR EACH MOLE OCTANE"# #"COMBUSTED THERE ARE 8 MOLE CARBON"# #"DIOXIDE EVOLVED"#, i.e. so approx. #49*mol# carbon dioxide gas.........which represents a mass of over #2*kg#.

Questions like this often ask you to estimate the volume occupied by the gas under standard conditions. Can you do this?