How much carbon dioxide is released when a #1*L# volume of octane is combusted?

1 Answer
anor277
Apr 12, 2017

Let us suppose that we use a #1*L# of octane to when we drive our motor...............

Explanation:

We reproduce your given equation:

#C_8H_18(l) +25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#

I halved the stoichiometric equation to make the arithmetic a bit easier.

#"Moles of octane"# #=# #(1*cancelLxx10^3*cancel(mL*L^-1)xx0.703*cancel(g*mL^-1))/(114.24*cancelg*mol^-1)=6.15*mol#

And given the stoichiometry, #"FOR EACH MOLE OCTANE"# #"COMBUSTED THERE ARE 8 MOLE CARBON"# #"DIOXIDE EVOLVED"#, i.e. so approx. #49*mol# carbon dioxide gas.........which represents a mass of over #2*kg#.

Questions like this often ask you to estimate the volume occupied by the gas under standard conditions. Can you do this?

Related questions
See all questions in Stoichiometry
Impact of this question
1085 views around the world
You can reuse this answer
Creative Commons License