# How much carbon dioxide is released when a 1*L volume of octane is combusted?

Apr 12, 2017

Let us suppose that we use a $1 \cdot L$ of octane to when we drive our motor...............

#### Explanation:

${C}_{8} {H}_{18} \left(l\right) + \frac{25}{2} {O}_{2} \left(g\right) \rightarrow 8 C {O}_{2} \left(g\right) + 9 {H}_{2} O \left(l\right)$
$\text{Moles of octane}$ $=$ $\frac{1 \cdot \cancel{L} \times {10}^{3} \cdot \cancel{m L \cdot {L}^{-} 1} \times 0.703 \cdot \cancel{g \cdot m {L}^{-} 1}}{114.24 \cdot \cancel{g} \cdot m o {l}^{-} 1} = 6.15 \cdot m o l$
And given the stoichiometry, $\text{FOR EACH MOLE OCTANE}$ $\text{COMBUSTED THERE ARE 8 MOLE CARBON}$ $\text{DIOXIDE EVOLVED}$, i.e. so approx. $49 \cdot m o l$ carbon dioxide gas.........which represents a mass of over $2 \cdot k g$.