What are the concentrations with respect to bromide, iodide, and hydronium ion for a solution prepared by mixing #150*mL# of #HI(aq)# at #0.1*mol*L^-1# concentration, and #50*mL# of #HBr(aq)# at #0.05*mol*L^-1# concentration?

1 Answer
Apr 15, 2017

Answer:

We assume (reasonably) that the volumes are additive...........

Explanation:

And thus the total volume of solution is #(50+150)*mL#, i.e. #0.200*L.#

For each species we remember that #"concentration"="moles"/"volume"#, and thus #"number of moles"="volume"xx"concentration"#

#[I^-]=(0.150*Lxx0.1*mol*L^-1)/(0.200*L)=0.075*mol*L^-1#.

#[Br^-]=(0.50*Lxx0.05*mol*L^-1)/(0.200*L)=??*mol*L^-1#.

#[H_3O^+]=(0.150*Lxx0.1*mol*L^-1+0.50xx0.05*mol*L^-1)/(0.200*L)=?#.