# What are the concentrations with respect to bromide, iodide, and hydronium ion for a solution prepared by mixing 150*mL of HI(aq) at 0.1*mol*L^-1 concentration, and 50*mL of HBr(aq) at 0.05*mol*L^-1 concentration?

Apr 15, 2017

We assume (reasonably) that the volumes are additive...........

#### Explanation:

And thus the total volume of solution is $\left(50 + 150\right) \cdot m L$, i.e. $0.200 \cdot L .$

For each species we remember that $\text{concentration"="moles"/"volume}$, and thus $\text{number of moles"="volume"xx"concentration}$

$\left[{I}^{-}\right] = \frac{0.150 \cdot L \times 0.1 \cdot m o l \cdot {L}^{-} 1}{0.200 \cdot L} = 0.075 \cdot m o l \cdot {L}^{-} 1$.

[Br^-]=(0.50*Lxx0.05*mol*L^-1)/(0.200*L)=??*mol*L^-1.

[H_3O^+]=(0.150*Lxx0.1*mol*L^-1+0.50xx0.05*mol*L^-1)/(0.200*L)=?.