# Question #48b84

Apr 13, 2017

We use the relationship, $\text{Concentration"="Moles of solute"/"Volume of solution.}$

#### Explanation:

And thus we solve for..........

$\text{Volume of solution"xx"concentration"="Moles of solute}$

(we assume, here, REASONABLY, that the volume of the solvent will not change overmuch when the calcium chloride salt is dissolved in it).

So $\text{Moles of solute} = 1 \cdot L \times 0.10 \cdot m o l \cdot {L}^{-} 1 = 0.10 \cdot m o l$.

And this represents a mass of $0.10 \cdot m o l \times 110.98 \cdot g \cdot m o {l}^{-} 1$

$= 11.10 \cdot g$.