# Question #b7424

Apr 14, 2017

C)

#### Explanation:

Let acceleration of the wagons be $= a$

Given the engine exerts a force $= 16000 N$ on $10$ wagons.

Mass of ten wagons $m = \text{Mass of one wagon" xx "Number of wagons}$
$\implies m = 1000 \times 10$
$\implies m = 10000 k g$

Applying Newton’s second law of motion we get
$F = m a$
$\implies a = \frac{F}{m} = \frac{16000}{10000} = 1.6 m {s}^{-} 2$

Again applying Newton's second law of motion to fine the force applied by 9th wagon on 10th wagon $= \text{mass of tenth wagon"xx"acceleration of tenth wagon}$
$= 1000 \times 1.6 = 1600 N$