Question #b7424

1 Answer
A08
Apr 14, 2017

C)

Explanation:

Let acceleration of the wagons be #= a#

Given the engine exerts a force #=16000 N# on #10# wagons.

Mass of ten wagons #m = "Mass of one wagon" xx "Number of wagons"#
#=>m = 1000 xx 10#
#=>m = 10000 kg#

Applying Newton’s second law of motion we get
#F= ma#
#=>a=F/m = 16000/10000 = 1.6 ms^-2#

Again applying Newton's second law of motion to fine the force applied by 9th wagon on 10th wagon #="mass of tenth wagon"xx"acceleration of tenth wagon"#
#=1000xx1.6=1600N#

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