Question #5a26c Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer ali ergin Apr 19, 2017 #f^(-1)(x)=+-sqrt(2x+10)# Explanation: #y=1/2 x^2-5# #"solve for x"# #y+5=1/2x^2# #2(y+5)=x^2# #2y+10=x^2# #x=+-sqrt(2y+10)# #"substitute y=x"# #y=+-sqrt(2x+10)# #f^(-1)(x)=+-sqrt(2x+10)# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 974 views around the world You can reuse this answer Creative Commons License