Question #7a9ae

Apr 22, 2017

We need to determine molar equivalence.......

Explanation:

Magnesium oxidizes according to the following stoichiometric equation:

$M g \left(s\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow M g O \left(s\right)$

$\text{Moles of metal} = \frac{10 \cdot g}{24.3 \cdot g \cdot m o {l}^{-} 1} = 0.412 \cdot m o l$.

And thus we need half an equivalent of dioxygen gas.........i.e.

$\frac{1}{2} \times 0.412 \cdot m o l \times 32.0 \cdot g \cdot m o {l}^{-} 1 = 6.58 \cdot g$ ${O}_{2}$ gas........

What is the mass of the oxide collected?