Question #53cfd

1 Answer

Answer:

#x^2+y^2-6x-10y+18=0#

Explanation:

Equation of a circle,given center coordinates and radius is
#(x-x_1)^2 +(y-y_1)^2=r^2#
Here #x_1#= 3 & #y_1# = 5.
#:.# Equation of the required circle is

#(x-3)^2+(y-5)^2=4^2#
#x^2-6x+9+y^2-10y+25=16#
#x^2+y^2-6x-10y+18=0#