# Question #53cfd

Sep 26, 2017

${x}^{2} + {y}^{2} - 6 x - 10 y + 18 = 0$

#### Explanation:

Equation of a circle,given center coordinates and radius is
${\left(x - {x}_{1}\right)}^{2} + {\left(y - {y}_{1}\right)}^{2} = {r}^{2}$
Here ${x}_{1}$= 3 & ${y}_{1}$ = 5.
$\therefore$ Equation of the required circle is

${\left(x - 3\right)}^{2} + {\left(y - 5\right)}^{2} = {4}^{2}$
${x}^{2} - 6 x + 9 + {y}^{2} - 10 y + 25 = 16$
${x}^{2} + {y}^{2} - 6 x - 10 y + 18 = 0$