# What is the concentration of an 18.9*g mass of ammonium nitrate dissolved in an 855*mL volume of solution?

Apr 18, 2017

$\text{Molarity"-="Moles of solute"/"Volume of solution} \equiv 0.276 \cdot m o l \cdot {L}^{-} 1$.
$\text{Molarity} = \frac{\frac{18.9 \cdot g}{80.05 \cdot g \cdot m o {l}^{-} 1}}{0.855 \cdot L} = 0.276 \cdot m o l \cdot {L}^{-} 1$.
And all we did here was to apply the definition of $\text{molarity}$, i.e. $\text{moles of solute per unit volume of solution}$.