What is the concentration of an #18.9*g# mass of ammonium nitrate dissolved in an #855*mL# volume of solution?

1 Answer
Apr 18, 2017

Answer:

#"Molarity"-="Moles of solute"/"Volume of solution"-=0.276*mol*L^-1#.

Explanation:

#"Molarity"=((18.9*g)/(80.05*g*mol^-1))/(0.855*L)=0.276*mol*L^-1#.

And all we did here was to apply the definition of #"molarity"#, i.e. #"moles of solute per unit volume of solution"#.

Would this solution be slightly acidic or slightly basic........?