# How many sigma-"bonds" and pi-"bonds" in ethylene?

Well, there is the ONE $\pi - \text{bond}$.
And I count $5 \times \sigma - \text{bonds}$: $4 \times C - H$, and $1 \times C - C$. So that is 6 bonds in total. Note that $4 \times H + 2 \times C$ gives 12 valence electrons, and thus the appropriate number of electrons to constitute the six $\text{2-centre, 2-electron}$ bonds.