Question #769cb

1 Answer
Apr 21, 2017

Answer:

#"Molarity" = 0.53M# #KClO_3#

Explanation:

#"Molarity"=("moles of the solute")/"volume of the solution" = "moles"/"liters"#

We can begin by converting grams to moles
*The molar mass for #KClO_3# is #122.55g#

#9.14g# x #(1 " mole")/(122.55g)#

#9.14cancel(g)# x #(1 " mole")/(122.55cancel(g)) = 0.0746 " moles"#

We have our moles and we have our volume but note: it's not in #L# so we must convert #mL# to #L#

We set up a conversion factor:

#(0.001L)/(1cancel(mL))# x #(140cancel(mL))/(1)= 0.14L#

Finally, using the formula for molarity given earlier...

#"Molarity"="moles"/"liters"#

#"Molarity" = (0.0746 " moles " KClO_3)/(0.14L)#

#"Molarity" = 0.53M# #KClO_3#