# Question #a46f3

Apr 23, 2017

(b) increase, is the correct answer.

#### Explanation:

Let the EMF of battery be ${V}_{o}$.
Power dissipated by the resistor is ${V}_{o}^{2} / R$.

Since the value of resistance is decreased. Let the new resistance be $R '$.
$\therefore$ power dissipated by the new resistor is ${V}_{o}^{2} / \left(R '\right)$.

Now $R ' < R$
$\implies \frac{1}{R '} > \frac{1}{R}$

$\implies \textcolor{red}{{V}_{o}^{2} / \left(R '\right) > {V}_{o}^{2} / R}$

$\therefore$ on decreasing the value of resistance, the power dissipated by resistor increases.

(b) increase, is the correct answer.