Question #091c8

Apr 23, 2017

The only tricky part is unit conversion.
$\frac{1 L}{1000 m L} \cdot \frac{1 m L}{1 c {m}^{3}} \cdot 250 c {m}^{3} = 0.250 L$

Answer is ${1.5055}^{23}$ $i o n s$ $C {l}^{1 -}$

Explanation:

$C a {\left(C l\right)}_{2} \to C {a}^{2 +} + 2 C {l}^{1 -}$
$n = c \cdot V$
$= \left(1 \frac{m o l}{L}\right) \cdot 0.250 L$
$= 0.250 m o l$

$N = {N}_{A} \cdot n$
$= \left(6.022 \cdot {10}^{23}\right) \frac{i o n s}{m o l} \cdot \left(0.250\right) m o l$
${1.5055}^{23}$ $i o n s$ $C {l}^{1 -}$