If pH-=8.25, what is [H_3O^+]?

1 Answer
Apr 27, 2017

By definition, $p H = - {\log}_{10} \left[{H}_{3} {O}^{+}\right]$.........

Explanation:

And thus $\left[{H}_{3} {O}^{+}\right] = {10}^{- 8.25} \cdot m o l \cdot {L}^{-} 1$

$= 5.0 \times {10}^{-} 9 \cdot m o l \cdot {L}^{-} 1$

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