# Question #a485f

Apr 27, 2017

The new volume would be 225 mL. Half the volume at twice the pressure.

#### Explanation:

This behaves according to Boyle's law which tells us that the volume of a gas and its pressure are inversely proportional. That means if one is doubled, the other is reduced by a factor of two. Triple the pressure, and the volume is one-third of what it was before.

In equation form:

${P}_{2} \cdot {V}_{2} = {P}_{1} \cdot {V}_{1}$

So,

${V}_{2} = \frac{{P}_{1} \cdot {V}_{1}}{P} _ 2$

In your problem, the doubling of the pressure can be taken to mean

${P}_{1} / {P}_{2} = \frac{1}{2}$

${V}_{2} = \left(\frac{1}{2}\right) {V}_{1}$
So, there is our result. If ${V}_{2}$ is 450, ${V}_{2}$ must be 1/2 of this.