# What is the molarity of #98%# #"H"_2"SO"_4#?

##### 1 Answer

Apr 28, 2017

Then that means you have

#"0.98 L H"_2"SO"_4 xx "1.84 g"/"mL" xx "1000 mL"/"L" ~~ "1803.2 g"#

and the mols of it would be:

#"1803.2 g H"_2"SO"_4 xx "1 mol"/"98.079 g" = "18.39 mols H"_2"SO"_4#

Therefore, the concentration is:

#("18.39 mols H"_2"SO"_4)/("1 L solution") ~~ color(blue)("18.4 M")#