GIven, #2NH_3(g)+2CH_4(g)+3O_2(g)rarr2HCN(g)+6H_2O(g)#... ...what mass of hydrocyanic acid would result from a #203.6*g# mass of ammonia?

1 Answer
May 1, 2017

Answer:

I gets..........over #300*g# of #HC-=N# given QUANTITATIVE reaction.

Explanation:

You have given the stoichiometric equation:

#2NH_3(g) + 2CH_4 + 3O_2(g) rarr 2HCN(g) + 6H_2O(g)#

#"Moles of ammonia"=(203.6*g)/(17.03*g*mol^-1)=11.9*mol#.

And now attend! The stoichiometry CLEARLY indicates that a given molar quantity of ammonia will give an EQUIMOLAR quantity of hydrogen cyanide. And given quantitative reaction, we should, with respect to hydrogen cyanide, get a mass of............

#11.9*molxx27.03*g*mol^-1=??g#

I think this is the old #"Andrussow Process"# which is performed to this day.