How do you prove the identity #(1/(1+x))^(a-b) + (1/(1+x))^(b-a) = 1# ?

1 Answer
Nov 26, 2017

The given identity is generally false.

Explanation:

The identity:

#(1/(1+x))^(a-b) + (1/(1+x))^(b-a) = 1#

is generally false.

For example, if #a=b# then:

#(1/(1+x))^(a-b) + (1/(1+x))^(b-a) = (1/(1+x))^0 + (1/(1+x))^0 = 1+1 = 2 != 1#