Question #9c009

1 Answer
May 1, 2017

Answer:

Well, #[Na^+]# has a #0.400*mol*L^-1# concentration..........

Explanation:

The concentration of #Na_2SO_4# was specified to be #0.200*mol*L^-1#. Because the formula contains two equiv of sodium ion, #[Na^+]=2xx0.200*mol*L^-1=0.400*mol*L^-1# WITH RESPECT TO SODIUM IONS. Do you see what's going on?

What is the concentration of nitrate ions in #0.100*mol*L^-1# #Ca(NO_3)_2(aq)#? Is it different from #[Ca^(2+)]#??