# Question #c0a79

The temperature drop is ${100}^{o} C - {25}^{o} C = {75}^{o} C = 75 K$
We use the formula: $Q = c \cdot m \cdot \Delta T$
$Q = 0.9 \frac{J}{\cancel{g} \cdot \cancel{K}} \times 100 \cancel{g} \times 75 \cancel{K} = 6750 J$
So it would be answer $B$