What is the value of #log_2(15)# ?
1 Answer
Nov 26, 2017
Explanation:
Use:
#log(2) ~~ 0.30103#
#log(3) ~~ 0.47712#
Then:
#log_2(15) = log(15)/log(2)#
#color(white)(log_2(15)) = log((3 * 10)/2)/log(2)#
#color(white)(log_2(15)) = (log(3)+log(10)-log(2))/log(2)#
#color(white)(log_2(15)) ~~ (0.47712+1-0.30103)/0.30103 = 1.17609/0.30103 ~~ 3.907#