Question #60b08

1 Answer
May 4, 2017

Answer:

#"Mole fraction, "chi_n="Moles of solute"/"Moles of all components in the solution"#

Explanation:

And thus #"moles of glucose"=(90*g)/(180.16*g*mol^-1)=0.50*mol#.

And #"moles of urea"=(30*g)/(60.06*g*mol^-1)=0.50*mol#.

And #"moles of water"=(162*g)/(18.01*g*mol^-1)=9.0*mol#.

So #chi_"glucose"=(0.50*mol)/((0.50+0.50+9.0)*mol)=0.05.#

And #chi_"urea"=(0.50*mol)/((0.50+0.50+9.0)*mol)=0.05.#

And #chi_"water"=(9.0*mol)/((0.50+0.50+9.0)*mol)=0.90.#

By the very way we define #"mole fraction"#, their SUM should be unity. Is this true in this case?