# Question #60b08

May 4, 2017

$\text{Mole fraction, "chi_n="Moles of solute"/"Moles of all components in the solution}$

#### Explanation:

And thus $\text{moles of glucose} = \frac{90 \cdot g}{180.16 \cdot g \cdot m o {l}^{-} 1} = 0.50 \cdot m o l$.

And $\text{moles of urea} = \frac{30 \cdot g}{60.06 \cdot g \cdot m o {l}^{-} 1} = 0.50 \cdot m o l$.

And $\text{moles of water} = \frac{162 \cdot g}{18.01 \cdot g \cdot m o {l}^{-} 1} = 9.0 \cdot m o l$.

So ${\chi}_{\text{glucose}} = \frac{0.50 \cdot m o l}{\left(0.50 + 0.50 + 9.0\right) \cdot m o l} = 0.05 .$

And ${\chi}_{\text{urea}} = \frac{0.50 \cdot m o l}{\left(0.50 + 0.50 + 9.0\right) \cdot m o l} = 0.05 .$

And ${\chi}_{\text{water}} = \frac{9.0 \cdot m o l}{\left(0.50 + 0.50 + 9.0\right) \cdot m o l} = 0.90 .$

By the very way we define $\text{mole fraction}$, their SUM should be unity. Is this true in this case?