# Question #cdf3b

##### 3 Answers

#### Explanation:

Every time you're looking for a solution's **molality**, you are looking for the **number of moles** of solute present for every *solvent*.

Your first step here will be to convert the number of grams of glucose to *moles* by using the compound's **molar mass**

#0.9813 color(red)(cancel(color(black)("g"))) * "1 mole glucose"/(180.156 color(red)(cancel(color(black)("g")))) = "0.005447 moles glucose"#

Next, convert the mass of water to *kilograms*

#8.9547 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.0089547 kg"#

Now, use the known composition of the solution--remember, solutions are **homogeneous mixtures**, which implies that they have the same composition throughout--to calculate the number of moles of glucose present in

#1 color(red)(cancel(color(black)("kg water"))) * "0.005447 moles glucose"/(0.0089547 color(red)(cancel(color(black)("kg water")))) = "0.6083 moles glucose"#

Therefore, you can say that this solution has a molality of

#color(darkgreen)(ul(color(black)("molality = 0.6083 mol kg"^(-1))))#

The answer is rounded to four **sig figs**, the number of sig figs you have for the mass of glucose.

#### Explanation:

**Molality** is defined as

The

We take our mass in grams and convert it to moles, but first, we need to find the molar mass of glucose

Then we convert our

**Solve**

The molality of the glucose solution is

#### Explanation:

Molality

The solute is glucose, and the solvent is water.

**Step 1:** Convert the given mass of glucose into moles of glucose by multiplying by the reciprocal of its molar mass.

Molar mass glucose=180.156 g/mol

https://www.ncbi.nlm.nih.gov/pccompound?term=glucose

**Step 2:** Convert the mass of water from grams to kilogram:

**Step 3:** Calculate molality of the solution using the equation at the top.