# If 0.276*mol silver chloride was collected from a reaction between silver nitrate and magnesium chloride, how many equiv magnesium nitrate were used?

May 6, 2017

One equiv of silver ion, $A {g}^{+}$, and half an equiv of $M g C {l}_{2} \left(a q\right)$.

#### Explanation:

And how do we know? Well, if we write the stoichiometric equation we have illustrated the stoichiometry:

$2 A g N {O}_{3} \left(a q\right) + M g C {l}_{2} \left(a q\right) \rightarrow M g {\left(N {O}_{3}\right)}_{2} \left(a q\right) + 2 A g C l \left(s\right) \downarrow$

Alternatively, we could write the net ionic equation...........

$A {g}^{+} + C {l}^{-} \rightarrow A g C l \left(s\right) \downarrow$

Given the stoichiometry, $\frac{0.276 \cdot m o l}{2}$ $M g C {l}_{2}$ were used..