# What is the percent by mass of #"12 M HCl"#?

##### 1 Answer

Knowing the concentration is about

#(12 cancel"mols HCl")/"L solution" xx "36.4609 g"/cancel"mol HCl" = "437.5308 g HCl"/"L solution"#

Based on the mass density, we can calculate the mass percent by converting the solution volume to its mass.

#("437.5308 g HCl")/cancel"L solution" xx cancel("1 cm"^(3))/("1.17 g solution") xx cancel"1 mL"/cancel("1 cm"^(3)) xx cancel"1 L"/(1000 cancel("mL")#

#= 0.374#

Or, about

See if you can calculate the concentration in **HINT**: Use a ratio of the molar concentrations of the