Question

Question #80035

Answer 1

`x=0,pi,(2pi)/3,(4pi)/3`

Explanation:

`2sin2x +2sinx =0`
`=>2xx2sinxcosx + 2sinx=0`
`=>2sinx (2cosx+1)=0`
`=>sinx=0 or cosx=-1/2`
`=>x=0,pi or x=(2pi)/3,(4pi)/3`