# Question #e6ee7

##### 1 Answer
May 5, 2017

The power will be the energy per photon, $\frac{h c}{\lambda}$, times the number, $n$, of photons emmitted each second:

$P = n \frac{h c}{\lambda}$

$\implies n = \frac{P \lambda}{h c} = \frac{330 \times 600 \cdot {10}^{- 9}}{6.63 \cdot {10}^{- 34} \times 3 \cdot {10}^{8}} \approx {10}^{21} \setminus {s}^{- 1}$