# Question #efc79

May 5, 2017

$\text{Molarity} \cong 5 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$.

And thus............

$\text{Molarity}$ $=$ $\frac{\frac{290.0 \cdot g}{58.44 \cdot g \cdot m o {l}^{-} 1}}{1 \cdot L} = 4.96 \cdot m o l \cdot {L}^{-} 1.$

This is impossibly salty sea water. You are out by an order of magnitude. This site reports a salinity of $35 \cdot g \cdot {L}^{-} 1$