Question #71dab

1 Answer
Jan 29, 2018

#x=e^2#

Explanation:

#x*(Lnx)^2=4e^2#

After taking natural logarithm both sides, this equation became

#Ln(x*(Lnx)^2)=Ln(4e^2)#

#Lnx+Ln((Lnx)^2)=Ln4+Ln(e^2)#

#Lnx+2Ln(Lnx)=2Ln2+2#

After setting #u=Lnx#, it became

#u+2Lnu=2+2Ln2#

Hence #u=2#

Thus,

#Lnx=2#, so #x=e^2#