Question

Question #7229d

Answer 1

The original pressure was `250*mm*Hg`...........

Explanation:

Old Boyle's Law holds that for a given quantity of gas, at a given temperature, `P` varies inversely according to `V`

`i.e. Pprop1/V`, and thus `PV=k`, where `k` is some constant of proportionality; and thus the defining relationship when we solve for `k`:

`P_1V_1=P_2V_2`

And thus `P_1=(P_2V_2)/V_1=(500*mm*Hgxx0.25*L)/(0.50*L)`

`=250*mm*Hg`.

How many atmospheres of gas pressure does this represent? Is the drop in pressure consistent with the details of the experiment?