Question #7229d

1 Answer
May 7, 2017

Answer:

The original pressure was #250*mm*Hg#...........

Explanation:

Old Boyle's Law holds that for a given quantity of gas, at a given temperature, #P# varies inversely according to #V#

#i.e. Pprop1/V#, and thus #PV=k#, where #k# is some constant of proportionality; and thus the defining relationship when we solve for #k#:

#P_1V_1=P_2V_2#

And thus #P_1=(P_2V_2)/V_1=(500*mm*Hgxx0.25*L)/(0.50*L)#

#=250*mm*Hg#.

How many atmospheres of gas pressure does this represent? Is the drop in pressure consistent with the details of the experiment?