Question

What is the `"molality"` of pure water?

Answer 1

Large...........`>50*mol*kg^-1`

Explanation:

`"Molality"="Moles of solute"/"Kilograms of solvent"`,

and so if we assume a `1*kg` mass of water,............(what is the volume?).........then

`"Molality"=((1000*g)/(18.01*g*mol^-1))/(1*kg)=??mol*kg^-1.`

And this value is quite comparable to water's `"molarity"`?