What is the "molality" of pure water?

May 8, 2017

Large...........$> 50 \cdot m o l \cdot k {g}^{-} 1$

Explanation:

$\text{Molality"="Moles of solute"/"Kilograms of solvent}$,

and so if we assume a $1 \cdot k g$ mass of water,............(what is the volume?).........then

"Molality"=((1000*g)/(18.01*g*mol^-1))/(1*kg)=??mol*kg^-1.

And this value is quite comparable to water's $\text{molarity}$?