Question #18188

1 Answer
May 8, 2017

Answer:

Let us assume a #100*g# mass of gas..........

Explanation:

And thus there are:

#(20*g)/(32.0*g*mol^-1)=0.625*mol# with respect to #"dioxygen"#.

And #(80*g)/(28.0*g*mol^-1)=3.33*mol# with respect to #"dinitrogen"#.

And since the molar quantity relates directly to the number of molecules, #O_2:N_2~=1:5#.