Question

Question #18188

Answer 1

Let us assume a `100*g` mass of gas..........

Explanation:

And thus there are:

`(20*g)/(32.0*g*mol^-1)=0.625*mol` with respect to `"dioxygen"`.

And `(80*g)/(28.0*g*mol^-1)=3.33*mol` with respect to `"dinitrogen"`.

And since the molar quantity relates directly to the number of molecules, `O_2:N_2~=1:5`.