Question #b92c3

1 Answer
Jan 30, 2018

See the explanation.

Explanation:

Given:

#color(red)(1-cos^2 theta=0#

We must find the value of #color(red)(theta# using reference angles

Reference Angle is the acute angle between the terminal side of #theta# and the x-axis.

We are given

#color(red)(1-cos^2 theta=0#

Subtract #color(blue)(1# from both sides

#color(red)(1-cos^2 theta - color(blue)(1=0 - color(blue)(1#

#color(red)(cancel 1-cos^2 theta - color(blue)(cancel 1=0 - color(blue)(1#

#-cos^2 theta =0 - 1#

#-cos^2 theta =- 1#

Divide both sides by #(-1)#

#(-cos^2 theta)/(-1) =(- 1)/(-1)#

#cos^2 theta =1#

Take square root on both sides to simplify

#sqrt(cos^2 theta) =sqrt(1#

#cos theta =+-1#

#rArr cos (0 ^{\circ})=1, cos (180 ^{\circ})=-1#

Quadrantal Angle:

An angle with terminal side on the x-axis or y-axis.

Do Quadrantal Angles have Reference Angles?

Both the angles, # (0 ^{\circ}) and (180 ^{\circ})#, are quadrantal angles and hence they do not have reference angles.