What is the molarity of hydrochloric acid in a solution that contains a #3.65*g# mass of #HCl(g)# in #500*mL# aqueous solution?

1 Answer
May 9, 2017

Answer:

#"Molarity"-="Moles of solute"/"Volume of solution"#

Explanation:

And here, #"molarity"=((3.65*g)/(36.5*g*mol^-1))/(500*mLxx10^-3*L*mL^-1)=0.200*mol*L^-1#.

Is the calculation consistent dimensionally?

And thus if it is #0.200*mol*L^-1# with respect to hydrogen chloride, it is #0.200*mol*L^-1# with respect to #H_3O^+#, AND #Cl^-#.

What is the #pH# of this solution?