# Question af8d7

$\frac{16}{3}$.
$B {r}_{3} {O}_{8}$
Oxygen has an oxidation state of −2# when it is present in most compounds. (https://en.wikipedia.org/wiki/Oxidation_state)
Since the sum of oxidation state number of neutral compound is $0$, sum of the oxidation number of bromine should equal to the opposite of oxygen's.
$- \left(- 2\right) \cdot \frac{8}{3} = \frac{16}{3}$