Question #38bc1

1 Answer
May 15, 2017

Answer:

#p_text(O₂) = "1.1 bar"; p_text(N₂) = "0.045 bar"; p_text(tot) = "1.2 bar"#

Explanation:

Calculate #p_text(O₂)#

From the Ideal Gas Law,

#pV = nRT = (m/M)RT#

#p = (mRT)/(MV) = (8 color(red)(cancel(color(black)("g"))) × "0.083 14 bar"·color(red)(cancel(color(black)("L·K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(32.00 color(red)(cancel(color(black)("g·mol"^"-1"))) × 5 color(red)(cancel(color(black)("L")))) = "1.1 bar"#

Calculate #p_text(N₂)#

STP is defined as and 0 °C and 1 bar.

Since the temperature does not change, we can use Boyle's Law to calculate the pressure of the nitrogen.

#p_1V_1 = p_2V_2#

#p_2 = p_1 × V_1/V_2 = "1 bar" × (0.224 color(red)(cancel(color(black)("L"))))/(5 color(red)(cancel(color(black)("L")))) = "0.045 bar"#

Calculate #p_text(tot)#

#p_text(tot) = p_text(O₂) + p_text(N₂) = "(1.1 + 0.045) bar= 1.2 bar"#