Question #eb759

$\text{Option D.....}$
$\text{Molarity"="Moles of solute"/"Volume of solution}$, and thus has units of $m o l \cdot {L}^{-} 1$.
And in $1 \cdot L$ of $3.5 \cdot m o l \cdot {L}^{-} 1$ $K N {O}_{3}$, there are.......................
$1 \cdot L \times 3.5 \cdot m o l \cdot {L}^{-} 1 = 3.5 \cdot m o l$ solute............with respect to $\text{potassium nitrate}$.