# What mass of "calcium carbide" gives a 1*L volume of acetylene under standard conditions?

May 14, 2017

This reactor uses calcium carbide as its hydrocarbon source..........

#### Explanation:

And follows the stoichiometric equation:

color(blue)(Ca^(2+)[""^(-)C-=C^(-)](s) + 2H_2OrarrCa(OH)_2 + HC-=CH(g)uarr)

We assume you want $1 \cdot L$ of acetylene gas under standard conditions of temperature and pressure, which (depending on the standard) is $0$ ""^@C and $100$ $k P a$

Using the Ideal Gas equation with the appropriate gas constant, we solve for $n = \frac{P V}{R T}$

$= \textcolor{red}{1 \cdot \text{bar"xx1*L)/color(red)(8.314xx10^-2*L*"bar} \cdot {K}^{-} 1 \cdot m o {l}^{-} 1 \times 273.15 \cdot K}$

$= 0.0440 \cdot m o l$.

And so we need a mass of ............................................

$0.0440 \cdot m o l \times 64.1 \cdot g \cdot m o {l}^{-} 1 = 2.81 \cdot g$ with respect to $\text{calcium carbide}$.