What mass of #"calcium carbide"# gives a #1*L# volume of acetylene under standard conditions?

1 Answer
May 14, 2017

Answer:

This reactor uses calcium carbide as its hydrocarbon source..........

Explanation:

And follows the stoichiometric equation:

#color(blue)(Ca^(2+)[""^(-)C-=C^(-)](s) + 2H_2OrarrCa(OH)_2 + HC-=CH(g)uarr)#

We assume you want #1*L# of acetylene gas under standard conditions of temperature and pressure, which (depending on the standard) is #0# #""^@C# and #100# #kPa#

Using the Ideal Gas equation with the appropriate gas constant, we solve for #n=(PV)/(RT)#

#=color(red)(1*"bar"xx1*L)/color(red)(8.314xx10^-2*L*"bar"*K^-1*mol^-1xx273.15*K)#

#=0.0440*mol#.

And so we need a mass of ............................................

#0.0440*molxx64.1*g*mol^-1=2.81*g# with respect to #"calcium carbide"#.