What is the thickness of an iron plate that has a mass of #0.25g#, and an area of #25cm^2#. #rho_"iron"=19gcm^-2#?

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Answer 1 · 2017-05-15T12:50:48

#"Thickness"~=0.005*mm#

I think you are one the right track........

#rho_"density"="mass"/"volume"#

And of course, #"volume"=lxxbxxw#, where #l="length"#, #b="breadth"#, and #w="width"# (#"lbw"!="leg before wicket"#).

So, #"volume"="mass"/rho_"density"=lxxbxxw#

And thus #w("width")="mass"/(rhoxxlxxb)#

#=(0.25*g)/(19*g*cm^-3xx25*cm^2)=5.26xx10^-4*1/(1/"cm")#

#5.26xx10^-4*cm-=5.26xx10^-3*mm#

What is the thickness of an iron plate that has a mass of #0.25*g#, and an area of #25*cm^2#. #rho_"iron"=19*g*cm^-2#?