What is the thickness of an iron plate that has a mass of #0.25*g#, and an area of #25*cm^2#. #rho_"iron"=19*g*cm^-2#?

1 Answer
May 15, 2017

Answer:

#"Thickness"~=0.005*mm#

Explanation:

I think you are one the right track........

#rho_"density"="mass"/"volume"#

And of course, #"volume"=lxxbxxw#, where #l="length"#, #b="breadth"#, and #w="width"# (#"lbw"!="leg before wicket"#).

So, #"volume"="mass"/rho_"density"=lxxbxxw#

And thus #w("width")="mass"/(rhoxxlxxb)#

#=(0.25*g)/(19*g*cm^-3xx25*cm^2)=5.26xx10^-4*1/(1/"cm")#

#5.26xx10^-4*cm-=5.26xx10^-3*mm#