Question #e71b7

1 Answer
May 16, 2017

Answer:

You need to supply 23 kJ of heat.

Explanation:

The formula for the quantity of heat #"q"# is

#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#

where

#m color(white)(ll)=# the mass of the object
#C color(white)(ll)=# its specific heat capacity
#ΔT =# its change in temperature

In this problem,

#m color(white)(ll)= "72 g"#
#C color(white)(ll)= "4.184 J·°C"^"-1""g"^"-1"#
#ΔT = "75 °C"#

#q = 72 color(red)(cancel(color(black)("g"))) × "4.184 J"·color(red)(cancel(color(black)("°C"^"-1""g"^"-1"))) × 75 color(red)(cancel(color(black)("°C"))) = "23 000 J" = "23 kJ"#