# Question #4fe76

May 16, 2017

Let the volume, $V = 1 \text{L}$, then we know that the mass, $m = 1.2 \text{g}$.

Find number of moles using the Ideal Gas Law:

$P V = n R T$

where $P = 745 \text{Torr}$, $T = {293}^{\circ} \text{K}$ and $R = 62.364 \text{L Torr"/"K mol}$

Solve the equation for n:

$n = \frac{P V}{R T}$

Substitute in the know values:

$n = \left(\left(745 \text{Torr")(1"L"))/((62.364 "L Torr"/"K mol")(293^@"K}\right)\right)$

The molecular mass is

$\frac{m}{n}$

$29.4 \text{g"/"mol}$