Question #5f0d5

1 Answer
May 19, 2017

Answer:

#0.124molN_2#

Explanation:

We'll use the ideal-gas equation for this problem.

First we must convert each unit into the appropriate unit for the equation:

#347mL(1L)/(10^3mL) = 0.347L#

#6680t o r r(1 atm)/(760t o r r) = 8.79 atm#

#27 ^oC + 273 = 300K#

Now, we'll use the ideal-gas equation, and solve it for quantity (in #mol#):

#n = (PV)/(RT)#

#n = ((8.79atm)(0.347L))/((0.08206(L-atm)/(mol-K))(300K)) = 0.124 molN_2#