Question

Question #5f0d5

Answer 1

`0.124molN_2`

Explanation:

We'll use the ideal-gas equation for this problem.

First we must convert each unit into the appropriate unit for the equation:

`347mL(1L)/(10^3mL) = 0.347L`

`6680t o r r(1 atm)/(760t o r r) = 8.79 atm`

`27 ^oC + 273 = 300K`

Now, we'll use the ideal-gas equation, and solve it for quantity (in `mol`):

`n = (PV)/(RT)`

`n = ((8.79atm)(0.347L))/((0.08206(L-atm)/(mol-K))(300K)) = 0.124 molN_2`