Question #edd07

1 Answer
Jan 8, 2018

#pi/2#

Explanation:

For a sine function in a form of #asin(bx)+c#, #absa# represents the amplitude of the function, #((2pi)/b)# represents the period, and #c# represents the midline.

Since 4 is multiplied by #x#, we solve the following:
#p=(2pi)/4#
#p=pi/2#
That is the answer!
Note that the negative #pi# in the function does not affect the period it.
To help our understanding, we have our function graphed. We see that the distance between each set of "peaks" is #pi/2#.
graph{3sin(4x-pi) [-10, 10, -5, 5]}